The bitwise AND is True only if both bits are set, the bitwise OR is true if either bits are set, You can use a mask value to check if certain bits have been set, If we wanted to check whether bits 1 and 3 were set, we could mask the number with 10 (the value if bits 1 and 3)

Bitwise AND

The bitwise AND is True only if both bits are set. The following example shows the result of a bitwise AND on the numbers 23 and 12.

You can use a mask value to check if certain bits have been set. If we wanted to check whether bits 1 and 3 were set, we could mask the number with 10 (the value if bits 1 and 3) and test the result against the mask.

#include <stdio.h>
int main()
{
int num, mask = 10;
printf("Enter a number: ");
scanf("%d", &num);
if ((num & mask) == mask)
puts("Bits 1 and 3 are set");
else
puts("Bits 1 and 3 are not set");
return 0;
}

Bitwise OR

The bitwise OR is true if either bits are set. The following shows the result of a bitwise OR on the numbers 23 and 12.

You can use a mask to ensure a bit or bits have been set. The following example ensures bit 2 is set.

#include <stdio.h>

int main()
{
int num, mask = 4;

printf("Enter a number: ");
scanf("%d", &num);

num |= mask;

printf("After ensuring bit 2 is set: %d\n", num);

return 0;
}

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