Δείτε ένα άλλο πέρασμα γ από το παράδειγμα αξίας για να το καταλάβετε καλύτερα. Το ακόλουθο παράδειγμα μετατρέπει έναν αριθμό 1 και 30.000 που δακτυλογραφούνται μεταξύ από το χρήστη στις λέξεις.
#include <stdio.h>
void do_units(int num);
void do_tens(int num);
void do_teens(int num);
int main()
{
int num, residue;
do
{
printf("Enter a number between 1 and 30,000: ");
scanf("%d", &num);
} while (num < 1 || num > 30000);
residue = num;
printf("%d in words = ", num);
do_tens(residue/1000);
if (num >= 1000)
printf("thousand ");
residue %= 1000;
do_units(residue/100);
if (residue >= 100)
{
printf("hundred ");
}
if (num > 100 && num%100 > 0)
printf("and ");
residue %=100;
do_tens(residue);
putchar('\n');
return 0;
}
void do_units(int num)
{
switch(num)
{
case 1:
printf("one ");
break;
case 2:
printf("two ");
break;
case 3:
printf("three ");
break;
case 4:
printf("four ");
break;
case 5:
printf("five ");
break;
case 6:
printf("six ");
break;
case 7:
printf("seven ");
break;
case 8:
printf("eight ");
break;
case 9:
printf("nine ");
}
}
void do_tens(int num)
{
switch(num/10)
{
case 1:
do_teens(num);
break;
case 2:
printf("twenty ");
break;
case 3:
printf("thirty ");
break;
case 4:
printf("forty ");
break;
case 5:
printf("fifty ");
break;
case 6:
printf("sixty ");
break;
case 7:
printf("seventy ");
break;
case 8:
printf("eighty ");
break;
case 9:
printf("ninety ");
}
if (num/10 != 1)
do_units(num%10);
}
void do_teens(int num)
{
switch(num)
{
case 10:
printf("ten ");
break;
case 11:
printf("eleven ");
break;
case 12:
printf("twelve ");
break;
case 13:
printf("thirteen ");
break;
case 14:
printf("fourteen ");
break;
case 15:
printf("fifteen ");
break;
case 16:
printf("sixteen ");
break;
case 17:
printf("seventeen ");
break;
case 18:
printf("eighteen ");
break;
case 19:
printf("nineteen ");
}
}
και η παραγωγή του προγράμματος θα είναι η ακόλουθη:
Enter a number between 1 and 30,000: 12345
12345 in words = twelve thousand three hundred and forty five |
|
